A car runs at a velocity of v(t) = e-t + 3t + 1, where t is measured in seconds. Find the distance travelled by the car in the first second?

Question

anonymous · Answer

Curiousmathstudent lets be curious about it .... and solve together !

anonymous · Answer

The distance traveled during a small dt time is given by:
$$distance = \int_{t1}^{t2}v(t)dt$$
Substituting, we get

$$distance = \int_{0}^{1}(e^{-t}+3t+1)dt = [-e^{-1}+\frac{3\times1^2}{2}+1 - -e^{-0}+\frac{3\times0^2}{2}+0]$$

Simplify to get your answer :)

Hope this helps.

anonymous · Answer

Gee thanks (:

anonymous · Answer

You are most welcome :)