I've never done exponential notation before and its completely boggling my mind, how would you go about solving (81x^-4y^8)^-1/4(xy^1/4)
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Question

anonymous · Answer

can you use equation button down there?

anonymous · Answer

$$(81x ^{-4}-4y ^{8})^{-1/4}(xy ^{1/4})$$

anonymous · Answer

OK, you mean simplify not solve.

Do you know the rules for powers?

anonymous · Answer

not at all

anonymous · Answer

It's more straightforward if you know them, want me to explain them?

anonymous · Answer

please

anonymous · Answer

First one

$$a^p * a^q = a^{p+q}$$

anonymous · Answer

its pretty much a foreign language. im terrible at math

anonymous · Answer

How about 2^2 + 2^3 = 2^(2+3) = 2^5 (concrete example of Rule1

anonymous · Answer

okay that makes sense

anonymous · Answer

It shouldn't cos I accidentally put a plus instead of a *, lol.

So you do a ^2 * b^5 = ?

anonymous · Answer

Do you want me to find you a site where u can study the rules?

(8 of them).

anonymous · Answer

im taking a placement test to enroll in courses for college this fall

anonymous · Answer

Once u know the rules, powers are pretty easy.

anonymous · Answer