Question

how do i solve y=x^2-4

Answer 1

x=-2 and x=2

Answer 2

is a sum of differences equation so it simplifies to (x-2)(x+2)

Answer 3

and then find the zeros x-2+0 and x+2+0

Answer 4

us formula a^2 -b^2 =(a-b)(a+b)

Answer 5

and you will get from your equation because you have there y=x^2 -2^(2)
what is equal with (x-2)(x+2)
- so in this case you have y=(x-2)(x+2)

(x-2)(x+2)=0 ---- x-2=0 --- x=2
x+2=0 --- x=-2