If g(x) = x2 - 2x - 8, solve g(x) ≤ 0
Hmm... Wanna learn how to do this?
yes
We can make it 'less scary' by changing g(x) to y.
so, y = x^2 -2x -8 We want y to equal less than or equal to 0.
Do you know how to factor this?
As in how to factor y = x2 - 2x - 8 ?
(x+2)(x-4)
yes
Perfect! Now, next question: What shape is this equation?
idk :(
Not a problem! Just remember: if you have x^2 in your equation, what will it be? A line? A circle? A square? A parabola? A triangle?
a parabola
{x|-2 ≤ x ≤ 4}; [-2, 4]
perfect! Now, is our parabola shaped more like a U (opening up) or a ^ (opening down)?
And yeah, that is our answer, but do you know *why*?
Hint: to remember if a parabola is going up or down, look at the sign in front of the x^2
down because of the nagative???
g(x) = x2 - 2x - 8
That was our original question.
So is there a positive or a negative in front of the x squared?
so its facing up
Perfect! And when you factored as (x-4)(x+2), where does that mean we place our points on the graph?
Hint: it's (x-4)(x+2)=0 where the y is 0
x=4 so 4,0 x=-2 so -2,0???
That's right!
Now, here's where we solve: where on the graph is the line below y = 0? Here's a picture of it: http://www.wolframalpha.com/input/?i=g%28x%29+%3D+x^2+-+2x+-+8
(That's why I asked for the direction of the graph. If it was upside down, our answer would be totally different)
thank you so much . i apreciate that you helped me understand
No problemo! Feel free to 'fan' me if you want to find me easily for future help! I like walking folks through to let them find answers on their own like this. :P
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