Question

6x^4-13x^2+6=0

solve

Answer 1

\[6(x ^{2})^{2}-(9+4)x ^{2}+6=0\]
Can u proceed from here

Answer 2

Put y = x^2. The equation becomes
6y^2 - 13y + 6 = 0
The discriminant is
d = 169 - 144 > 0
so you have two real solutions for y
y1 = (13 - 5)/12 = 2/3 and y2 = (13 + 5)/12 = 3/2

Since the original equation is of fourth degree, you need to have 4 solutions. So yo have to pose
x1 = + sqrt(2/3)
x2 = - sqrt(2/3)
x3 = + sqrt(3/2)
x4 = -sqrt(3/2)

sqrt = square root