Question

can sin^2A-cos^2A=-1?

Answer 1

now it can't be

we alredy know tht sin^2 + cos^2 =1

replc value to get answer

Answer 2

lets rplc cos^2

cos^2 = 1 - sin^2

sin^2 - 1 + sin^2
2sin^2 - 1


which is not equal to -1

Answer 3

\[\sin ^{2}\theta -\cos ^{2}\theta= -1\]
\[\sin^{2}\theta=-(1-\cos ^{2}\theta)\]
\[\sin ^{2}\theta=-\sin ^{2}\theta\]
this implies that for this equation \[\sin \theta\]
has fixed value 0