The sum of any three distinct natural numbers arranged in ascending order is 200 such that the second number is a perfect cube . How many possible values are there for this number?

Question

anonymous · Answer

Ain't many cases.

anonymous · Answer

i dont know if im misunderstanding the problem or not....
anywhos, there are only 5 perfect cubes less than 200:
1, 8, 27, 64, and 125.
1 cant possible by the middle number (there is no natural number less than 1 to be the first number)
125 also cant be the middle number, (only 75 left for the first and second number, none of which are larger than 125)
So im guessing the remaining three possible? anyone else agree/disagree?

anonymous · Answer

thats what i was thinking as well but i wasnt sure if that's what the question was asking for

anonymous · Answer

Seems a bit too straightforward for a number theory question.

anonymous · Answer

yeah, it didnt seem as complicated as problems of this nature usually are...thats why im not sure if its correct lol

anonymous · Answer

i think thats right