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sum of 3 consecutive odd no.s is a perfect sq between 200 and 400 . wat is the sq root of this sum
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i dont really have a method for this <.< answer is 15 >.>
the three numbers are 73, 75, and 77, their sum is 225, square root of 225 is 15.
ok
i guess i can explain my thought process, although its weak at best. if you let n, be the middle number, then the 3 consecutive odd numbers are: \[n-2, n, n+2\] their sum is 3n. so you want 3n to add up to a perfect square. that means that n needs to be factorable into 3*(some other square). so i randomly picked squares and came across 25. 3*25 is 75. 3*3*25 = 225, so on and so forth.
THANK YOU AGAIN You're d best BTW how old are u
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25 :) lol
ok
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