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find the F (the anti-derivative?) of f''(x)=3/(x)^(1/2), where at f'(4)=7 and F(4)=20
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yay integration! finally something interesting..
we cant integrate yet, my calc instructor wont allow it. He wants us to find the anti derivatives
f"(x) = 3/x^(1/2) = 3*x^(-1/2), integrate this.
Integral is anti derivative..
Integral of (3x^(-1/2)) = 3x^((-1/2)+1)/((-1/2)+1)
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f'(x) = 3x^(1/2)/(1/2) = 6x^(1/2) + C
f'(4)=7 => 6*sqrt(4) + C = 7 6*2 + C = 7 12+c = 7, c = 5
f'(x) = 6x^(1/2) + 5
repeat the process: integrate (f'(x)) => get _________ + C plug in F(4) = 20 and get the original F
thank you.
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