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Mathematics 21 Online
OpenStudy (anonymous):

In , is a right angle. Find to the nearest tenth of a degree. http://mapleta.mivu.org/mapleta/web/Alg2aMm000/Public_Html/Algebra%202A%20Unit%20Test/unit%204/cp%204.1-4.3%20Q9.jpg

OpenStudy (anonymous):

In , is C a right angle. Find m<B to the nearest tenth of a degree.

OpenStudy (amistre64):

algebra unit test hmm....

OpenStudy (anonymous):

quiz, it just shows as a test -- checking answers!

OpenStudy (amistre64):

B is the one with an x right?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

given that they give you all 3 measures of sides; you can take your pick from any of the tangent inverse functions

OpenStudy (anonymous):

21.8 degrees (180 ArcTan[24/60]/\[Pi])

OpenStudy (amistre64):

perhaps like?: tan(x) = 24/60 x = tan-1(2/5)

OpenStudy (anonymous):

\[(180 \text{ArcTan}[24/60]/\pi ) \]

OpenStudy (amistre64):

if your calculator is already set up in degrees; robs will be off.

OpenStudy (amistre64):

if in radians, mine will be off :)

OpenStudy (amistre64):

test it by sin(90); it should be 1

OpenStudy (anonymous):

put your calculator in degree mode first so you don't need to mess around with any conversions

OpenStudy (anonymous):

then you have a plethora of options. you can compute \[\tan^{-1}(\frac{24}{60})\] \[\sin^{-1}(\frac{24}{64.6})\] or even \[\cos^{-1}(\frac{60}{64.6})\]

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