Question

What are the x and y intercepts of -8x + 4y = 32

Answer 1

x - intercepts set y = 0 and solve for x via\[-8x=32\]
\[x=\frac{32}{-8}=-4\] so x intercept is (-4,0)

Answer 2

divide it all by 32 and simplify :)

Answer 3

y - intercept put x = 0 and solve
\[4y=32\]
\[y=\frac{32}{4}=8\]

Answer 4

y - intercept is (0,4)

Answer 5

sensei would find working with fractions = "simplifying"

Answer 6

\[-8x + 4y = 32\]
\[\frac{-8x}{32} + \frac{4y}{32} = \frac{32}{32}\]
\[\frac{-x}{4} + \frac{y}{8} = 1\]
when x = 0; y = 8
when y = 0; x= -4 :)

Answer 7

im assuming you typoed your y intercept :)

Answer 8

Refer to the attached visual aid.

Answer 9

yes a typo sorry. should be (0,8)