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Mathematics 22 Online
OpenStudy (anonymous):

What is the area of a regular hexagon?

OpenStudy (anonymous):

3*sqrt(3)/2 * a*a

OpenStudy (anonymous):

The area of a regular hexagon of side length x is given by : \[A=3\sqrt{3}/2 *x ^{2}\]

OpenStudy (anonymous):

Thankyou.

OpenStudy (anonymous):

How Can I derive the area of regular Hexagon?

OpenStudy (amistre64):

just for kicks ... it is the area of 2 iso traps: the area of an iso trap is (b1+b2)h/2 b1 = 2s; b2 = s; h=s*sqrt(3)/2 (or s*sin(60)) (2s+s)(s)(sqrt(3)) (3s)(s)(sqrt(3)) 3s^2 sqrt(3) --------------- = ------------- = ----------- 2 2 2

OpenStudy (amistre64):

dropped a 2 lol ; divided by 4

OpenStudy (amistre64):

then double it to get: 3s^2 sqrt(3)/2

OpenStudy (anonymous):

Sorry! that was easy thanks.........I should have tried it on my own

OpenStudy (amistre64):

it was easy :) i think most people do it with the area of each triangle piece and multiply by 6 to get the same results

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