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OpenStudy (anonymous):
3*sqrt(3)/2 * a*a
OpenStudy (anonymous):
The area of a regular hexagon of side length x is given by :
\[A=3\sqrt{3}/2 *x ^{2}\]
OpenStudy (anonymous):
Thankyou.
OpenStudy (anonymous):
How Can I derive the area of regular Hexagon?
OpenStudy (amistre64):
just for kicks ...
it is the area of 2 iso traps:
the area of an iso trap is (b1+b2)h/2
b1 = 2s; b2 = s; h=s*sqrt(3)/2 (or s*sin(60))
(2s+s)(s)(sqrt(3)) (3s)(s)(sqrt(3)) 3s^2 sqrt(3)
--------------- = ------------- = -----------
2 2 2
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OpenStudy (amistre64):
dropped a 2 lol ; divided by 4
OpenStudy (amistre64):
then double it to get: 3s^2 sqrt(3)/2
OpenStudy (anonymous):
Sorry! that was easy thanks.........I should have tried it on my own
OpenStudy (amistre64):
it was easy :) i think most people do it with the area of each triangle piece and multiply by 6 to get the same results