What is the area of a regular hexagon?
3*sqrt(3)/2 * a*a
The area of a regular hexagon of side length x is given by : \[A=3\sqrt{3}/2 *x ^{2}\]
Thankyou.
How Can I derive the area of regular Hexagon?
just for kicks ... it is the area of 2 iso traps: the area of an iso trap is (b1+b2)h/2 b1 = 2s; b2 = s; h=s*sqrt(3)/2 (or s*sin(60)) (2s+s)(s)(sqrt(3)) (3s)(s)(sqrt(3)) 3s^2 sqrt(3) --------------- = ------------- = ----------- 2 2 2
dropped a 2 lol ; divided by 4
then double it to get: 3s^2 sqrt(3)/2
Sorry! that was easy thanks.........I should have tried it on my own
it was easy :) i think most people do it with the area of each triangle piece and multiply by 6 to get the same results
Join our real-time social learning platform and learn together with your friends!