Suppose the line y = 6x - 6 is tangent to the curve y = f(x) when x = 3. If Newton's method is used to locate a root of the equation f(x) = 0 and the initial approximation is x1 = 3, find the second approximation x2.
newtons method is to use the derivative to determine the equation of a tangent line to the curve; and follow it down till it zeros out on the x axis; then use that new x value in f(x) to determine a new point for derivitations
it like playing on chutes and ladders :)
Haha. wish it were that easy...any chance you would be willing to solve for the second approximation for me?
sure, but I cant quite see what the original f(x) is spose to be yet is x=3 your first x value? its hard to make out the problem
y = 6x - 6 zeros out at x=1; so we have to evaluate f(1) to get a new tangent line to play on
f'(x) = 0 .... i think you had a typo
x1 = 3 was the first guess; next is x2, which equals 1
that is what they are seeking for if i parse the question correctly
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