Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Suppose the line y = 6x - 6 is tangent to the curve y = f(x) when x = 3. If Newton's method is used to locate a root of the equation f(x) = 0 and the initial approximation is x1 = 3, find the second approximation x2.

OpenStudy (amistre64):

newtons method is to use the derivative to determine the equation of a tangent line to the curve; and follow it down till it zeros out on the x axis; then use that new x value in f(x) to determine a new point for derivitations

OpenStudy (amistre64):

it like playing on chutes and ladders :)

OpenStudy (anonymous):

Haha. wish it were that easy...any chance you would be willing to solve for the second approximation for me?

OpenStudy (amistre64):

sure, but I cant quite see what the original f(x) is spose to be yet is x=3 your first x value? its hard to make out the problem

OpenStudy (amistre64):

y = 6x - 6 zeros out at x=1; so we have to evaluate f(1) to get a new tangent line to play on

OpenStudy (amistre64):

f'(x) = 0 .... i think you had a typo

OpenStudy (amistre64):

x1 = 3 was the first guess; next is x2, which equals 1

OpenStudy (amistre64):

that is what they are seeking for if i parse the question correctly

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
3 hours ago 3 Replies 0 Medals
Arriyanalol: help
3 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 3 Medals
Jaded012023: Please tell me what you all think of this song
6 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
6 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!