What is the solution to the system below? -3x-y=-3 9x+3y=9 (3, 3) (3, -3) no solution infinite solutions on the line
explain to me how to do this like how to start this off
Ok, so your possibilities are: Infinitely many solutions. No solutions. One solution. I put this in this order because you'll want to check each one on it's own.
So first, to check to see if it is infinite solutions: If you have 2 equations (eq1 and eq2) If eq1 = k * eq2 (or vice versa) where k is any number, then you will have infinite solutions.
Can you see a number which ,if you multiplied one of the equations by it, would give you the other equation?
ok so i have to slove the equations first right??
You can if you like.
It's not really needed for 2 of the 3 cases.
for example -3x-y=-3 -y=-3x-3
That's not quite solved yet. Need to get rid of the - in front of the y.
did you mean to add 3x on both sides?
Assuming you're solving for y.
Also yes, it should be a +3x
yea m sloving for y
Ok, so you add 3x to both sides you'll have: -y = 3x - 3
Then multiply both sides by -1
y=-3x-3
y = -3x + 3
You have to multiply -1 times both the 3x and the -3
y i dnt get that y do i need to * -1??
to get rid of the - in front of the y.
ok i already did that o the y is now postive so its postive y=-3x-3
\(-3x-y=-3\) +3x +3x \(\implies -y = 3x - 3\) *-1 *-1 \(\implies y = -3x + 3\)
No, you have to multiply the whole right side by -1. \(-1(3x - 3) = -3x + 3\)
ok i already did that o the y is now postive so its postive y=-3x-3
yes that is wat i did soooo... wat do i do next do i slove the nxt equation?? qwhich would be y=-3x-3
NO. It's y = -3x + 3
ok i already did that o the y is now postive so its postive y=-3x-3
o ok
now do the same thing for the other equation.
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