Question

Find the absolute maximum and absolute minimum values of f on the given interval. (Round all answers to two decimal places.)
f(x) = xe^(-x^2/128)
[-3, 16]

Answer 1

find criticle point

Answer 2

criticle point is found by setting the derivative equals to 0

Answer 3

there's a local maximum at (8, 8e^(-1/2))

Answer 4

I am guessing whoever asks this is long gone

Answer 5

the absolute maximum is given by 8*e^(-1/2)

local minimum and absolute minimum is given by -8*e^(-1/2)

Answer 6

oh, sorry, local minimum is -3*e^(-1/2) and so is absolute minimum

Answer 7

sorry, it's -3*e^(-9/64)...JESUS...

Answer 8

OMG. -3*e^(-9/128)...sorry...jesus christ