Find the absolute maximum and absolute minimum values of f on the given interval. (Round all answers to two decimal places.)
f(x) = xe^(-x^2/128)
[-3, 16]

Question

Find the absolute maximum and absolute minimum values of f on the given interval. (Round all answers to two decimal places.)
f(x) = xe^(-x^2/128) 
[-3, 16]

anonymous · Answer

find criticle point

anonymous · Answer

criticle point is found by setting the derivative equals to 0

anonymous · Answer

there's a local maximum at (8, 8e^(-1/2))

anonymous · Answer

I am guessing whoever asks this is long gone

anonymous · Answer

the absolute maximum is given by 8*e^(-1/2)

local minimum and absolute minimum is given by -8*e^(-1/2)

anonymous · Answer

oh, sorry, local minimum is -3*e^(-1/2) and so is absolute minimum

anonymous · Answer

sorry, it's -3*e^(-9/64)...JESUS...

anonymous · Answer

OMG. -3*e^(-9/128)...sorry...jesus christ