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Mathematics 17 Online
OpenStudy (salina):

I attach file need help,TY

OpenStudy (salina):

OpenStudy (salina):

I need help ,Please!

OpenStudy (anonymous):

This is the same question Natala Asked

OpenStudy (salina):

not that

OpenStudy (salina):

how you solve n

OpenStudy (anonymous):

Natala was also confused at it ! do u know the power rule ?

OpenStudy (anonymous):

if i say r^n = (r^n-1)(r) would i be wrong tell me?

OpenStudy (salina):

I don't need formula , I need to know how you solve find n

OpenStudy (anonymous):

and also tell me wt is the last term of gp

OpenStudy (salina):

yes but n=?

OpenStudy (salina):

I need to find n

OpenStudy (anonymous):

just tell me last term representation of last term in gp .... i'l show u how it works trust me

OpenStudy (anonymous):

if there n terms in gp then gp is a,ar,....ar^n-1 here ar^n-1 is the last term ....

OpenStudy (salina):

From her: s = a - a r * r^n-1 --------- -2 u substitution n=?

OpenStudy (anonymous):

i told u wts an in the question \[a _{n}\]?

OpenStudy (anonymous):

it is the last term

OpenStudy (anonymous):

\[a _{n}=ar ^{n-1}\]

OpenStudy (salina):

\[33=\frac{a _{1}(1-(-2))^{n-1}}{-2}\]from here how I find n

OpenStudy (anonymous):

lets take the numerator only a(1- (-2)^n) this is how it is now a - a (-2)^n-1 (-2) ^ this the last term

OpenStudy (anonymous):

last term in ur first question = 48

OpenStudy (anonymous):

go thru the attachment again ...

OpenStudy (anonymous):

salina i'm sorry i've to go somewhere.... but i'm telling u go thru the attch. again u'l find the answer use this r^n = r^n-1(r)

OpenStudy (anonymous):

OpenStudy (salina):

thank you Taina can you do me number 19

OpenStudy (anonymous):

Do it the same way as Tatiana just showed you for the other.

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