Question

solve and check
3d^2+14d-5=0

Answer 1

d = -5,1/3

Answer 2

did you try factoring? if not, use quadratic formula

Answer 3

do i have to show

Answer 4

factor 15-1

Answer 5

hint:now that problemsolver gave you the answer, you know how to factor it

Answer 6

please show work if you can I want to fully understand

Answer 7

\[3d ^{2} +14d -5 = (3d -1 )(d+5)\]
\[(3d-1) = 0\]
\[3d = 1\]
\[d = 1/3\]
\[d + 5 = 0\]
\[d\]

Answer 8

you want to write it as
\[(3d+\text{something})(d+\text{something else})=0\]

Answer 9

d= -5

Answer 10

Not sure why it truncated.

Answer 11

and since you have the answer as
\[-5,\frac{1}{3}\] you know it must factor as
\[(d+5)(3d-1)=0\]

Answer 12

thank u....