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If x is a positive angle smaller than 90° and cos(x) = 1/3, then sin(x) =
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hi
sinx = sqrt(1 - cos^2x) = sqrt(8/9) = 2sqrt2 / 3
ok - i used the trig identity sin^2x + cos^x = 1
ok
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thanks
no probs - plz click on good answer to close the question
yes
ty
jimmyrep great! :)
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yes he is
cosx=1/3=adjacent/hypenuese so the opposite side can be found be Pythagorean thm 1^2+(opposite)^2=3^2 1+(opposite)^2=9 (opposite)^2=9-1 (opposite)^2=8 opposite=sqrt{8} sinx=opposite/hypenuese=sqrt{8}/3
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