Question

If X and Z are independent and P(X) = .6, P(Z) = .3, compute:
A) P(x U z)
B) P (x intersection z)

Answer 1

A)0.6+0.3=0.9
b)0.6*0.9=0.54

Answer 2

the upside down U means intersection right

Answer 3

Nope U means Union

Answer 4

i know but i couldnt do the upside down one on the computer so i put intersection

Answer 5

The probability of a person over the age of 53 developing cancer is .06, and the probability that she/he develops heart problems is .08. If a patient over 53 is selected at random, what is the probability that the patient will develop:

A) None of these deseases?
B) At least one of the diseases?
C) Both of the diseases?

Answer 6

can u help me on this one?

Answer 7

please

Answer 8

\[P(X\cup Z)=.72\]

\[P(X\cap Z)=.18\]