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lets start with \[f\circ g \]
\[g(-1)=10\] but \[f(10)\] does not exist so we can forget about \[f\circ g(-1)\]
\[g(2)=0\] and \[f(2)=-1\] so the only ordered pair for \[f\circ g\] is\[ \{(0,-1)\}\]
now we repeat the process for \[g\circ f\] \[f(0)=-7\] but there is no \[g(-7)\] so toss that one \[f(1)=2\] \[g(2)=0\] so we have the ordered pair (1,0) similarly \[f(2)=-1\] \[g(-1)=10\] so we get (2,10) and the ordered pairs for \[g\circ f\] are \[\{(1,0),(2,10)\}\]
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