Question

Alchemista more C++

Answer 1

alchemista like my friend is also teaching me stuff but he's also a newbie, he only took C++ for like a semester or something.. anyway is there a way for this:
1) Program asks for a number of digits
2) I enter the number say 3
3) The program asks for digit 1: I enter it and so forth until digit 3.
4) The program shows me the minimum or maximum of those digits.
Is there like a command max(a,b,c) or min(a,b,c) or how do I do this?

Answer 2

For two digits I have:
#include <math.h>
#include <conio.h>
#include <iostream>
#include "stdafx.h"
using namespace std;

int main()
{float First_number, Second_number, Minimum_value;
cout<<"First number=";
cin>>First_number;
cout<<"Second number=";
cin>>Second_number;
if (First_number<Second_number)
Minimum_value=First_number;
else Minimum_value=Second_number;
cout<<"Minimum value="<<Minimum_value<<"\n";
system ("pause");
return 0;
}

Answer 3

You can use for loop for that

Answer 4

how?

Answer 5

You store the "greatest" and compare each new one against the current greatest.

Answer 6

Thats for max

Answer 7

so what would the greatest be? what if i want it to be the infinity?

Answer 8

For min its the other way around.

Answer 9

pseudo code:

min = first digit
loop:
input = next digit
if input < min: min = input
break when done

Answer 10

you loop should go up to number of digits

Answer 11

float min () {
int digits;
float current, value;
cout << "Count: " << flush;
cin >> digits;
cout << "Value: " << flush;
cin >> current;
while(--digits > 0) {
cout << "Value: " << flush;
cin >> value;
if ( value < current )
current = value;
}
cout << "Min: " << current << endl;
}