20) The Everton College store paid $1804 for an order of 48 calculators. The store paid $9 for each scientific calculator. The others all graphing calculators cost $58 each. How many of each type of calculator was ordered?
c@9 = (1804 - 48(9))/(58-9) maybe .... i always get this one confused
solve \[9x+58(84-x)=1804\] so get your answer
sensei always does it in one step. probably right
anyway what i wrote was wrong. solve \[9x+58(48-x)=1804\]
lets see if im right :) 28(9) + 20(58) ?= 1804 252 + 1160 ?= 1804 1412!=! 1804 ... might got em backwards then ...
yep; had em backwards lol
reasoning as follows. x is number of $9 for a total of 9x dollars. if x are $9 calculators then the rest (48-x) cost $58 for a total of 58(48-x) dollars.
therefore one expression for the total is \[9x+58(48-x)\] and the other expression for the total is $1084 because you are told that
so set \[9x+58(48-x)=1084\] and solve for x
1804 .. but yeah
b@y = (z -t(x))/(y-x) amount@58 = (1804 - 48(9))/(58-9)
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