A box of candy contains three orange and five cherry hot sticks. If four hot sticks are chosen at random from the box, what is the probability that no more than one will be orange? Round your answer to one decimal place.

Question

A box of candy contains three orange and five cherry hot sticks.   If four hot sticks are chosen at random from the box, what is the probability that no more than one will be orange?   Round your answer to one decimal place.

anonymous · Answer

is it 4/15

anonymous · Answer

or .25

anonymous · Answer

find the probability that none are orange and then find the probability that one is orange and then add

amistre64 · Answer

a tree diagram would be helpful maybe

anonymous · Answer

so 5/16

anonymous · Answer

lets go slow

amistre64 · Answer

this appears to be the sample space:

cccc
ccco
ccoc
cocc
occc
ccoo
coco
occo
cooc
ococ
oocc
cooo
ocoo
ooco
ooco

did I miss any?

anonymous · Answer

thats what i was doing

amistre64 · Answer

5/15 would be good if thats the case :)  or simplified to 1/3

anonymous · Answer

Satellite, when you are done would you mind checking my work on Prob. here: http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e21fc9b0b8ba00f8f00615f

zarkon · Answer

is this with or without replacement?

anonymous · Answer

i think its 5/16

amistre64 · Answer

since there are only 3 oranges; you cant really go to a 16th spot can you?

amistre64 · Answer

that and 5*3 = 15 options to begin with

anonymous · Answer

but it is out of all options possible, which is 16

anonymous · Answer

right?

amistre64 · Answer

how are there 16 options possible?

zarkon · Answer

you know that the items listed in your sample space are not equally likely...right?

amistre64 · Answer

0 orange:  cccc

1 orange: ccco  ccoc  cocc  occc

2 orange: ccoo coco occo cooc ococ oocc

3 orange: cooo ocoo ooco ocoo

that was a concern of mine too :)

zarkon · Answer

Can I get an answer to this....is this with or without replacement?

amistre64 · Answer

when in doubt; assume both  :)

zarkon · Answer

they give different answers

anonymous · Answer

oooo 
cccc
occc
cocc
ccoc
ccco
oocc
ococ
coco
ccoo
oooc
ooco
ocoo
cooo
occo
cooc

anonymous · Answer

16

amistre64 · Answer

oooo is not a possibility since there are only 3 to begin with; but that would assume its WITH replacement in order to pick it a forth time

anonymous · Answer

I would take a different approach; isn't it (3C1 * 5C3 + 3C0 * 5C4)/8C4?

zarkon · Answer

yes...that is the answer is the sampling is done without replacement

zarkon · Answer

hypergeometric distribution

anonymous · Answer

so I get 4/7

zarkon · Answer

i get 1/2

amistre64 · Answer

i get confused :)

anonymous · Answer

Mary has 30 hats. She has 5 green, 7 blue, 12 red, and 6 brown.   If she selects two hats at random, what is the probability that both hats are different colors?   Round your answer to two decimal places

anonymous · Answer

what about this??

zarkon · Answer

you really need to specify with or without replacement...they give different answers.

anonymous · Answer

the question didnt put with or without it just is wat i said

anonymous · Answer

For the wording I would assume without.

zarkon · Answer

I would assume that too...though the book should specify

anonymous · Answer

well its probably without

zarkon · Answer

doing a quick calculation I get  323/435