Question

Solve b^3=-8

Answer 1

b=-2

Answer 2

-2 * -2 * -2 =-8

Answer 3

I suppose we had better go along with the idea that there are 3 roots for a cubic

(b+2)(b^2-2b+4) gives in addition 2 complex roots i sqrt3 plus minus 1.

Answer 4

b^3 = (-2)^3
since it is an equality and the powers/indices r same => bases also have to be same

therefore b = -2

Answer 5

b^3 - 8 = 0 is a suitable and permitted rearrangement that provides a polynomialk subject to the FTA.

Answer 6

in junior classes, the concept of complex roots is not taught.............
to me the questioner appeared to be from a junior class, so I advised accordingly....☺