Question

find the inverse: f(x)=(3x+1)/2....
my answer is f(x)= (2x-1)/3. is that right???

Answer 1

thats correct :)

Answer 2

and can i ask u something???
the function is one- to- one dont have the same y right??? if it's have the same y then it's not a function one to one right???

Answer 3

er...i dont really understand what you are asking >.<
a function is one-to-one if you look at the result of the function, and only one number could be the solution. For example:
if f(x) = 3x+2, and i say f(x) = 17, i can figure out that the only value of x that makes that work is x = 5:
\[3x+2 = 17 \Rightarrow 3x = 15 \Rightarrow x = 5\]
So this function is one-to-one. An example of a function that ISNT one-to-one is:
\[f(x) = x^2\]
we can see this because if i say f(x) = 25, what is x? it could be 5, but it could also be -5. Thus the function isnt one-to-one.
I hope this answers your question lol >.< sry for my speech

Answer 4

ok thanks... i dont know how to know a function is one to one...

Answer 5

easy.
1) switch x and y and solve for y. if you get one answer, then one to one

Answer 6

2) put
\[f(a)=f(b)\] and using algebra solve to get
\[a=b\]

Answer 7

3) graph the function and use "horizontal line test"