Question

question attached below

Answer 1

\int\limits_{1}^{e} (2x+e)/(x^2+ex)

Answer 2

i mean \[\int\limits_{1}^{e} (2x+e)/(x^2+ex)\]

Answer 3

oh there is meant to be a" dx "at the end as well

Answer 4

guess you want a u - sub for this one
put
\[u=x^2+ex\]
\[du=(2x+e)dx\]
\[u(1)=1+e\]
\[u(e)= e^2+e\] so get
\[\int_{1+e}^{e^2+e} \frac{du}{u}\]

Answer 5

gives
\[\ln(u)|_{1+e}^{e^2+e}\]
\[=\ln(e^2+e)-\ln(1+e)\]

Answer 6

\[=\ln(\frac{e^2+e}{1+e})=\ln(e)=1\]\]

Answer 7

thank math whiz