Mathematics
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OpenStudy (vishweshshrimali5):
A positive number when divided by 88 gives the remainder 8. What will be the remainder when this number id divided by 11 ?
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OpenStudy (anonymous):
3?
OpenStudy (anonymous):
lets try it. what number when divided by 88 gives a remainder of 8? well 88+8=96 for for one
OpenStudy (vishweshshrimali5):
Yes I have done hit and trial and what i have got is that the remainder = 8
OpenStudy (anonymous):
so i guess 3 is wrong because
\[\frac{96}{11}=8\tfrac{8}{11}\] so remainder is 8. shows you what i know!
OpenStudy (vishweshshrimali5):
But how will you prove it
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OpenStudy (vishweshshrimali5):
I want the whole explanation for it
OpenStudy (anonymous):
and we can try it again with
\[2\times 88 + 8\]
OpenStudy (anonymous):
oh now that we know it is 8, i think answer is easy enough
OpenStudy (vishweshshrimali5):
Yes that also gives remainder 8
OpenStudy (vishweshshrimali5):
But how will you prove it
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OpenStudy (anonymous):
because
\[88=8\times 11\] yes?
OpenStudy (vishweshshrimali5):
Right !
OpenStudy (vishweshshrimali5):
Now what to do ?
OpenStudy (anonymous):
so
\[n\times 88+8=11n+8\]
OpenStudy (vishweshshrimali5):
Now !
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OpenStudy (anonymous):
and when you divide
\[11n+8\] by 11 you get a remainder of 8
OpenStudy (vishweshshrimali5):
How ?
OpenStudy (anonymous):
since clearly11 divides 11n evenly!
OpenStudy (vishweshshrimali5):
Yes
OpenStudy (vishweshshrimali5):
And we get 8 as remainder
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OpenStudy (vishweshshrimali5):
Thanks
OpenStudy (anonymous):
that is all you need. 11 goes in to "11n" n times, so it goes in to 11n + 8 n times with a remainder of 8.yw
OpenStudy (vishweshshrimali5):
Thanks
OpenStudy (vishweshshrimali5):
But how did you get n×88+8=11n+8
OpenStudy (vishweshshrimali5):
I can't get that still ?
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OpenStudy (vishweshshrimali5):
Because if I will show that using hit and trial I got this
My teacher will give me zero marks
OpenStudy (vishweshshrimali5):
Please help !!!!
OpenStudy (anonymous):
what to you mean "hit and trial"? we proved it
OpenStudy (vishweshshrimali5):
How did we prove that n×88+8=11n+8
OpenStudy (anonymous):
just say "if n is divided by 88 and the remainder is 8, then
\[n=88k+8\] and therefore
\[n=11\times 8j+8\] since
\[88=11\times 8\]
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OpenStudy (vishweshshrimali5):
Ok
Then ?
OpenStudy (anonymous):
'thus upon dividing
\[n=11\times 8j+8\] by 11 we see that 11 divides
\[11\times 8j\] evenly giving a remainder of 8"
qed
aka
have a nice day
OpenStudy (vishweshshrimali5):
Thanks a lot satellite
OpenStudy (vishweshshrimali5):
Will you please help me in some more questions
OpenStudy (vishweshshrimali5):
Go to my profile page and then to the questions asked
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OpenStudy (anonymous):
post them be happy to
OpenStudy (vishweshshrimali5):
Ok