A fair die is rolled four times. The probability that each of the final three rolls is at least as large as the roll preceeding it is m/n in the lowest terms. Then n -10m = ?
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OpenStudy (anonymous):
Please stop spamming and wait patiently for a tutor to assist you with your problems.
OpenStudy (vishweshshrimali5):
KKKKKKK sorry
OpenStudy (vishweshshrimali5):
Hey!! Xcuseme Who are you polpak ? May I know please?
OpenStudy (anonymous):
Just a lego guy
OpenStudy (vishweshshrimali5):
What is lego guy ?
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OpenStudy (vishweshshrimali5):
I mean what does it mean ?
OpenStudy (vishweshshrimali5):
Hey You have 580 medals !!!!!!!!!! wow
OpenStudy (anonymous):
this question is a poser
OpenStudy (anonymous):
Others have more.
OpenStudy (vishweshshrimali5):
Hello satellite please help me !
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OpenStudy (vishweshshrimali5):
What is a poser !
OpenStudy (anonymous):
are u studying iit coaching
OpenStudy (vishweshshrimali5):
No but preparing for that but how do u know that man ?
OpenStudy (anonymous):
if the first roll is a1, then probability is 1
if the first roll is a 2 then probability is
\[(\frac{5}{6})^3\]
OpenStudy (anonymous):
that type of question comes in iit
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OpenStudy (vishweshshrimali5):
Yaa u are right amingad !
OpenStudy (anonymous):
it is easy take 4 turn as 36c4
OpenStudy (vishweshshrimali5):
How do u got that satellite please explain !
OpenStudy (anonymous):
oh wait that is wrong. i need to read more carefully
OpenStudy (vishweshshrimali5):
Please take you time
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OpenStudy (vishweshshrimali5):
How do you got that amingad
OpenStudy (anonymous):
looks like coupon collectors problem
OpenStudy (vishweshshrimali5):
It may be
OpenStudy (anonymous):
what is probability of a record. gives harmonic series
OpenStudy (anonymous):
yikes now i have to think
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OpenStudy (vishweshshrimali5):
Amingad please explain step by step I can't understand it so fastly
OpenStudy (vishweshshrimali5):
I am a neophyte in this field you may think that
OpenStudy (anonymous):
fair dice consist of 6 numbers . so the the no of times get the highest probability of number will be 24 c4 my mistake i wrote 36 c4
OpenStudy (anonymous):
you lost me here for sure
OpenStudy (vishweshshrimali5):
What do you mean to say satellite ?
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OpenStudy (vishweshshrimali5):
Okkkkk amingad now is there any step left ?
OpenStudy (anonymous):
i mean i am lost completely.
OpenStudy (vishweshshrimali5):
Ohhhh you mean that it is a nice question then thanks a lot
OpenStudy (vishweshshrimali5):
Well satellite you can have a look at other questions
OpenStudy (anonymous):
12c3< m/ n so n has to be highest dice to be rolled
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OpenStudy (vishweshshrimali5):
Amingad will you please do me a favour
OpenStudy (anonymous):
yep it is tricky but good
OpenStudy (vishweshshrimali5):
can you write the answer in a single post and with each step explained
Because my teacher says that you will have to answer the question with each step explained or you will get no marks
OpenStudy (vishweshshrimali5):
Will you please do so ?
OpenStudy (vishweshshrimali5):
Are you answering the question amingad
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OpenStudy (zarkon):
\[\frac{7}{72}\]
OpenStudy (anonymous):
yep correct answer zarkon
OpenStudy (zarkon):
i know
OpenStudy (zarkon):
Just for fun...if we used an n-sided die the probability is
\[\frac{(n+1)(n+2)(n+3)}{24n^3}\]
OpenStudy (zarkon):
and if we rolled an n-sided die k times it would be
\[\frac{n(n+1)(n+2)\cdots(n+k-1)}{n^{k}k!}\]