A distribution center receives shipments from three different factories in quantities of 50, 35, and 20. Three times a product is selected at random. Find the probability that all three products came from the second factory.
1/3 times1/3times1/3 = 1/27
oh i don't think so
ok now i think so. sorry
haha i didnt think so
Total number is 50+35+20=105. I believe it should be \[(\frac{35}{105})^3\]
Oh, whoops, that's the same thing that was written before.
haha my problem changes everytime i answer it wrong. now the numbers are 50, 40, and 25
and it wants the probability that they came from the third factory
Well, the way I did it should work. Find the sum of all the units, then find the probability that a single unit came from the 3rd factory, and then cube the probability.
It said the answer was 0.009 is that what you woulda got?
I got 0.010
yeah i didnt get the answer they wanted either haha
Hm...I wonder why they're getting that.
It was a weird process but I figured it out, thanks for trying
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