Question

how would i solve the equation log4(x-4)=-3? wouldnt i take 4 to the -3 exponent to start? im lost

Answer 1

yes you would

Answer 2

you would write
\[4^{-3}=x-4\] and solve for x

Answer 3

assuming of course that your problem is
\[\log_4(x-4)=-3\]

Answer 4

thanks for the response. so would that be x-4=.016?

Answer 5

well lets see.

\[4^{-3}=x-4\]
\[x=4+4^{-3}=4+\frac{1}{64}\] whatever that is

Answer 6

how would I find the domain of a function \[\log _{2\left( 25-x ^{2} \right)}\]? I think it is (5,-5)