Can anyone help explain how to write an algebraic expression from a word problem with percentages?
Sure. Post the problem.
The final grade for this course is calculated by dividing total points earned by total points available, and a grade of 72% is required to earn a C. There are 618 points available in the first four weeks of the course and 255 points in the last two weeks of the course. If a student earns a grade of 63% in the first four weeks of the course, what percentage grade must the student earn in the last two week in order to earn a final grade of C? She will accept an answer that is expressed as a decimal.
can you help me?
yeah.
In the first four weeks of the course the student has earned 0.63*618=389 points. To earn a C in the course a student needs 0.72*(618+255)=629 points at the end of 6 weeks. The student has already earned 389 points and so needs another 629-389=240 points. There are 255 points available and the student needs to earn 240 of them So the student needs 240/255=0.94 or 94% in the last two weeks to get a C in the course.
i understand that for the most part, but she wants us to use 1 variable in writing the equation, how would you take that into account?
ok. I did it this way to kind of guide you through it but it can be written more succinctly. Hang on...
Okay. So we write and expression for total points earned divided by total points available and se that equal to the grade we want, i.e., 0.72:\[\frac{(0.63)(618)+255x}{873}=0.72\] Solve for x.
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