Question

The length of a rectangle is 5 meters more than its width. If the area is 66 square meters, what are the length and width?

Show all Work!

Answer 1

Let the width be x then length will be x + 5

Area = x(x + 5)

given area = 66 square meters

x(x + 5) = 66

x^2 + 5x = 66

x^2 + 5x - 66 = 0

(x + 11)(x - 6) = 0

x = -11, 6

ignore negative value

x = 6

width = 6 m

length = 6 + 5 = 11 m

Answer 2

Let the width be x then length will be x + 5

Area = x(x + 5)

given area = 66 square meters

x(x + 5) = 66

x^2 + 5x = 66

x^2 + 5x - 66 = 0

(x + 11)(x - 6) = 0

x = -11, 6

ignore negative value

x = 6

width = 6 m

length = 6 + 5 = 11 m

Answer 3

Let w=width
Then length = w+5 meters
Given Area is 66 sq meters.
Area is equal to length times the width and is 66 sq meters
(w+5) w = 66
w^2+5w =66
w^2 + 5w -66=0 (standard form)
factor
(w+11)(w-6)=0
w+11=0, w=-11,
w-6=0, w=6
Use the positive value w=6 and length equal w+5 or length =11
Just as chris also worked out above, that was a good answer.

Answer 4

thanks:-D

Answer 5

Thank you all