Question

(u^2+7u/u^2+3u-28)/(u/u+4)

Answer 1

divide and simplify

Answer 2

2^(2x) - 3(2^x) = 28

note that (2^x)^2 = 2^(2x)

if we let u = 2^x, this becomes
u^2 - 3u = 28
u^2 - 3u - 28 = 0
(u - 7)(u + 4) = 0

so either u - 7 = 0 ==> u = 7
or u + 4 = 0 ==> u = -4
but since u = 2^x, then u = -4 is extraneous

so u = 7 = 2^x
and converting to the log form, x = log_2 7 (or log base 2 of 7)

Answer 3

I think you confused me

Answer 4

no never

Answer 5

isn't is suppose to be x^2 not 2^x

Answer 6

or is that the same thing

Answer 7

no

Answer 8

it is same man

Answer 9

so what would be the fraction form of the answer

Answer 10

u/u is 1...i dont get it

Answer 11

Bryan, kindly check that you wrote the question correctly, because as I5starjordan says, u/u = 1. Thanks =)

Answer 12

use parentheses better