Question

FInd the exact value of the logarithmic expression:
log2...1

Answer 1

\[\log_{2}1 \]

Answer 2

again switch to exponential form

Answer 3

\[\log_2(1)=y\]
\[2^y=1\]

Answer 4

got it that far

Answer 5

this should convince you not only that
\[y=0\] but also that
\[\log_b(1)=0\] no matter what b is

Answer 6

right? because
\[b^0=1\] always

Answer 7

how do you get that y=0 little confused

Answer 8

no how do you go from 2y=1 to y=0

Answer 9

i see the rest of it

Answer 10

Anything power 0 is 1.

Answer 11

http://www.wolframalpha.com/input/?i=2^y+%3D+1