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What is the slope of (-1,-5) and (5,-5)
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inifinity
oh wait wrong way lol... it has no slope
y2-y1 / x2 - x1 -5--5 / 5--1 0 / 6 = 0
So would the slope be considered undefined?
yep cause it doesnt have one...
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I thought the slope is zero
Slope is zero, which is different than an undefined slope
A slope of zero means that as x changes, z remains the same. An undefined slope means that...well, slope is not defined
That's what I thought, so the slope = 0. which *is* a valid slope.
Thank you!
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