Question

C++: I think I need a bigger datatype but even long long int is not working. Here is a screenshot of my code: http://imgur.com/VtRkB

Answer 1

yucky computer programs lol

Answer 2

lol

Answer 3

how many "long" are you allowed to type?

Answer 4

Figured this is a pretty simple question so I will try it here before I head over to stack overflow.

Answer 5

imgur is giving me 404

Answer 6

Why don't you pastebin the code its much better than a screenshot

Answer 7

http://pastebin.com/

Answer 8

http://pastebin.com/HenCRw7v

Answer 9

I think only 2

Answer 10

It depends on the platform but a signed integer is from -2^31 to 2^31

Answer 11

This is the first time I've encountered something like this though so I am not even sure if I am doing it right typing any data type that is more than 1 word.

Answer 12

A long signed integer is from -2^63 to 2^63

Answer 13

*long long

Answer 14

one second.

Answer 15

I am using dev c++

Answer 16

Also you forgot to initialize the variable to 0

Answer 17

So it will simply take on the value that was there before it on the stack.

Answer 18

long long int n = 0;

Answer 19

Ok

Answer 20

Same error

Answer 21

"integer constant is too large for "long" type"

Answer 22

Don't need int
just long long

Answer 23

long long n = 0;

Answer 24

Fine now?

Answer 25

No, same error

Answer 26

Hmm

Answer 27

ah ok
I think I know what will help
Its complaining about the literal
try adding an l after the number or ll

Answer 28

600851475143ll I think

Answer 29

That did it

Answer 30

Cool, what does that mean?

Answer 31

its a long long literal

Answer 32

Anytime you have long or long long you need l or ll?

Answer 33

l is just long, ll is long long

Answer 34

Im sure you've seen something similar for floating point values

Answer 35

for instance 3.0f

Answer 36

never

Answer 37

alright

Answer 38

in any case be very careful with your types if you are going to be handling long long values

Answer 39

you don't want to truncate it at some point in the program

Answer 40

Ok, thanks a lot!

Answer 41

Actually one last thing, long is the implicit type for integer literals (at least for your compiler). So you only need ll for long long literals, for smaller values you do not need to explicitly append a single "l"