Question

in 1994 the life expectancy was 65.4 years in 2000 it was 68.3 years. Let E represent the life expectancy and t represent the years since 1994, use the function E(10)= the life expectancy in 2004, the linear function E(t) that fits the data is:

Answer 1

\[E(t) = \frac{y_2-y_1}{x_2-x_1}t + b\]\[E(t) = \frac{68.3-65.4}{2000-1994}t + 65.4\]

Answer 2

E(10) = 70.23333333