Question

2x^2-x-13=0

Answer 1

Plug it into the quadratic formula and see what you get

Answer 2

im not at the quadratic formula yet

Answer 3

that is what you have to do. write
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=2,b=-x,c=-13\]

Answer 4

then either the question is a typo, or you are stuck

Answer 5

because this one does not factor over integers

Answer 6

the original equation is the square root of 2x+1 is = to 2x-5

Answer 7

\[\sqrt{2x+1}=2x-5\]
2x+1=(2x-5)^2
2x+1=4x^2-20x+25
4x^2-22x+24=0
solve for x
2(2x^2-11x+12)=0
2(2x-3)(x-4)=0
x=3/2,4