Question

algebra 1 math!
write the equation of the line that is purpendicular to the graph of y=1/2 x + 6 and whose y-intercept is (0, -2)

write steps please (if you can)

Answer 1

Again? :S

Answer 2

LOL sorry

Answer 3

you don't have to answer

Answer 4

i will get.

Answer 5

lol.

Answer 6

Do u want the ans?

Answer 7

yeah

Answer 8

This guy is helping! ;)

Answer 9

y=mx+b
b= y value of y intercept=-2

for perpendicular lines the slopes has to be opposite of the reciprocal
so if 1 slope is a the other has to b -1/a

for this 1 the slope is 1/2 so the new line slope must be:
m=-2
so
y=-2x-2

Answer 10

The formula of a line is : \[y - y _{0} = m(x-x _{0})\]
Where y & x are variables; \[y _{0} & x _{0}\] are the coordinates of a point on the straight line - (0,2) in this case and m is the slope.

For a line to be perpendicular to another, their slopes must obey the relation mm'=-1.

The slope of a line is the coefficient of x when the coefficient of y is 1. If the coefficient of y is not 1, divide the equation by that (coefficient of y) to make it one.

Here the slope of the given equation is 1/2.
put it in the relation between the slopes (mm'=-1):
(1/2)m'=-1
=> m' = -2

now put the given point and the slope in the main formula for the line. that gives:
y-(-2)=-2x-(-2x0)
=> y= -2x -2