zed
(f/g)'= (gf'-g'f)/g²
Yeah, but apparently there's some new way that Zed invented
Not really
its not new, its just exactly what i just said. his trick is the thing above f and g are two separate functions
Yeah, it's the same. He invented nothing
I'm disappointed
but now that you're here, can you help me with it?
i gotta derive \[(-x ^{4}+5)/e ^{x}\]
What do you need help with? lol
follow your own advice
That's pretty easy
im just wondering what im supposed to do with e^x squared
-4x^3+x^4-5/e^x factor out the top and it should cancel
Leave it as e^x squared
It's not incorrect to leave it that way
zed, that can't be right...what you have...
how so?
unless e^x cancells
Yeah, e^x cancels top and bottom
Yeah, Paul, that wasn't a hard one at all
yeah. i got docked major points in cal 1 because i didnt always factor and reduce on the exams. its the difference between a C and a B
Z.E.D.
I was doing it in my head..Always look to reduce and cancel equivalents of one after taking derivative
Good job Zed
so the derivative of what i asked is itself?
No, Zed posted the solution...It's not exactly the same...An extra term appears
the derivative of e^x is always e^x
if that helps any
I think Paul needs step by step directions
ah i was so close, just a sign and x to the four.... i did know that the derivative of e^x is e^x thanks though... nah i didnt need steps so much, just was a bit lazy cause i thought i'd need a page to write the whole qquestion out, but ended up doing it in about 1/8th of a page.... yay us.
okay. if you need any more help just ask. differential calculus isnt too bad the algebra can get pretty tricky sometimes though
ALGEBRAAAAAAAAA! in the style of KHAAAAAAAN!!!!
Kilo Khan, Saifoo Khan, or Sal Khan?
whichever the one is from star trek
Ask Saifoo, he's part of the Khan family....He would know..
à la i mean, not in the style of.
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