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Why is the horizontal asymptote of f:x--> (2x+4)/(x-1) y=2 but not y=6? because doesn't (2x+4)/(x-1) become (2(x-1)+6)/(x-1)???
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2(0-1)+6 = 4/-1. no asymptote however 2x+4=0 x=2 so that is where the asymptote is. You are forgetting that when the equation is in this: 2(x-1)+6 form the +6 is not the x-incept
okay whoops sorry I typed the question in the wrong way but I understand now thankyou anyway!
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