help mee ! solve for x , write both solutions. 3x^2+2x-8=0
looks like someone is attempting to help...
i need your help. anywasss. plss help. ihts for a semester test.
a simple way to solve this equation is using the equation to find roots of quadratic equation: \[x = [-b \pm \sqrt{b^{2} - 4ac}]/2a\] other way of solving it would be factoring the equation to: (x + 2)(3x - 4) = 0
im confuseed noww
Really, why?
okay, if you foil the second equation, you should get the same equation as one you put on the question. Just solve (x+2) = 0 and (3x-4) = 0 then solve for x
thats the point i dont really get what x will be . nothing clickss. im stupid in math sorrry! worst subject since middle school.
heroo, what can x bee?
it would be -2 and (4/3)
Hold on a minute...
since this is a quadratic equation, there will be two answers. Do you understand the process?
I think she needs a more elaborate explanation
to understand the process
yess sortaa, i really dont gert how you got 4/3
okay, so you do understand that there are two roots/solutions to x, right?
yess
okay - so, what i did was to re-write the equation into two smaller equations. and determine solutions based on that smaller equations
another way of solving this equation is to use the first equation i gave you based on that quadratic equation is expressed in terms of: Ax^2 + Bx + C = 0
ok thanks , my friend got ihtt already(:
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