Find this equation for the line through (2,6) and perpendicular to y = -5/4x + 1

a. y = 5/4x + 7/2
b. y = -4/5x + 38/5
c. y = 4/5x + 22/5
d. y = -5/4x + 17/2

Question

Find this equation for the line through (2,6) and perpendicular to y = -5/4x + 1

a. y = 5/4x + 7/2
b. y = -4/5x + 38/5
c. y = 4/5x + 22/5
d. y = -5/4x + 17/2

anonymous · Answer

The slope of your original line is -5/4.  The slope of a perpendicular line is the opposite reciprocal of the original line (4/5).  This should be enough to identify the equation without doing any more calculations.

anonymous · Answer

So what's the answer?

anonymous · Answer

For a line to be perpendicular to $$y = \frac{-5}{4}x + 1$$ its slope must be the negative reciprocal of that slope. So the slope of the line you want is $$\frac{4}{5}$$ Since only one option has this slope you should know your answer