Question

3x^2-3x-36

Answer 1

either use roots of quadratic equation or factor the equation then solve for x

Answer 2

hey, here is everything

Answer 3

take 3 out to start
= 3(x^2 - x - 12)

Answer 4

Alright, it's not loading so here it is step by step

Answer 5

3x^2-3x-36 =
3(x^2-x-12) =
(x-3) (x+4)

final answers are: x= -4
x= +3

Answer 6

disregard the -3 factored
'cause it doesn't matter

Answer 7

So first factor out the 3

Answer 8

Those are the final aswers?

Answer 9

The x=3
amdx= -4 are the final answers

Answer 10

Do you need me to walk you through step by step

Answer 11

We haven't been solving the equasions, just factoring them. If that makes any sense . I don't know a thing about math, but we haven't been solving for the values of x. We've been rewriting the expressions

Answer 12

Okay, then for the sake of factoring, the answer is just:
(x-3)(x+4)

Answer 13

Oh, okay. Lol Thank you.

Answer 14

Okay, what's the next question?

Answer 15

2x^2-11x+14

Answer 16

Okay. The same thing applies to this equation

Answer 17

Only, because the 11 isn't a factor of two, you may have to solve by way of this equaiton;
+or- the square root of b^2-4(a)(c) all divided by 2

Answer 18

Hve you ever seen this equation?

Answer 19

I haven't.

Answer 20

Okay, it's from algeabra 1

Answer 21

But we've used a^2+b^2=(a-b)(a+b)

Answer 22

You can facto questions that don't follow the rules of regular factoring

Answer 23

Okay.

Answer 24

anyway, I'm working on it right now sorry

Answer 25

I don't understand. Because 11 isn't a factor of two, you have to what?

Answer 26

Now we have to use that equation I told you about, because no matter what you do, even if you take the 2 and multiply by 1, you'll still only have 14-2 which is not 11

Answer 27

First off, think of your equation as abc okay

Answer 28

A is whatever x^2 is

Answer 29

B is the x value or the second term in an equation: x^2 - x ←

Answer 30

Okay. And b is 11x?

Answer 31

And c is 14

Answer 32

Yes, but you don't need the x for this value. Also, because the - in fornt of the 11 is part of the equation, make sure to not forget it

Answer 33

so b= -11 and c=14

Answer 34

Okay.

Answer 35

your eqation is now this: -11+ or - the \[-11 + or - the \sqrt{-11^{2}}-(4)(2)\]

Answer 36

all of the variables after the squareroot sign are under the square root okay

Answer 37

Okay

Answer 38

The next step i: \[\sqrt{121 - 112}\]

Answer 39

now you have the square root of 9

Answer 40

the next step is: -11 + or - 3 / 2

Answer 41

when I say over 2, I mean the whole equation

Answer 42

Okay, I'm doing my best to follow.

Answer 43

I know it's confusing, here I'm going to try and attach a file again

Answer 44

Okay.

Answer 45

Okay, too many people are on. Log onto facebook really quick, but stay on here as well. Just open a new tab k. I'll post it there

Answer 46

I deactivated my facebook. Do you have an instant messenger?

Answer 47

I don't see you there, maybe I can email it to you

Answer 48

I do on yahoo

Answer 49

hey what's your messenger info

Answer 50

Ramona.windley@Hotmail.com

Answer 51

okay,are you online?

Answer 52

Yes

Answer 53

You;re bubble for gmail says you're not

Answer 54

gmail?

Answer 55

hotmail sorry

Answer 56

i sent the link to your hotmail, just log in