Question

Use the quadratic formula for (t^2 - 3)^2.

Answer 1

I got the answer in decimals by factoring by my teacher said it has to be in radical form.

Answer 2

are you trying to find the roots of

\[(t^2-3)^2\]

i.e. finding the solutions to \[(t^2-3)^2=0\]

?

Answer 3

Yes, the zeros (roots).

Answer 4

ok

\[(t^2-3)^2=0\]

take square root

\[(t^2-3)=\sqrt{0}=0\]

add 3

\[t^2=3\]

take square root again

\[t=\pm\sqrt{3}\]

Answer 5

And what would be the two zeros (or roots)? Can you go any farther and not have decimals?

Answer 6

that is it

\[t=\sqrt{3}\] and \[t=-\sqrt{3}\]

Answer 7

Oh! Wow, I can't believe I never understood that. Thank you, you just explained a bunch to me.

Answer 8

no problem