If A can do a job in 8 days and b can do the same job in 12 days, how long would it take them both to complete the job working together?
8 + 12 = 20 would take 20 days. \[\color{red}{\text{ok joemath, take it away}}\]
\[\frac{1}{\frac{1}{8}+\frac{1}{12}}\]
just kidding. solve \[(\frac{1}{8}+\frac{1}{12})t=1\] for t
one day i am going to figure out a snap way to explain this.
ends up being \[3x+4x=24\] but why this is obvious eludes me. joemath?
yeah >.< i just think of it like: d = rt the rate is inversely proportional to time, so i need to get the reciprocals of their times to get the "rates". Then i add the rates together, but i want time as an answer, so i take the reciprocal of my answer...... its gross.
you should have seem me with the jellybean problem. took maybe half an hour!
sounds intense o.O
no joemath no one thinks like that. must be some obvious way to do it. i mean look at the answer. right hand side of equal sign in lcm of 8 and 12. left hand side is \[\frac{24}{8}+\frac{24}{12}\] which for one thing means my solution is wrong. but still there must be some obvious reason for this yes?
i guess it has to do with the fact that you would use the LCM to get a common denominator for the fractions? and by the way, I think like that :( lol
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