Question

4p^2+12pq+9q^2 factor completely

Answer 1

\[(2 p+3 q)^2 \]

Answer 2

? how'd you get that? I got something completely different

Answer 3

Simplifying
4p2 + 12pq + 9q2 = 0

Reorder the terms:
12pq + 4p2 + 9q2 = 0

Solving
12pq + 4p2 + 9q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(2p + 3q)(2p + 3q) = 0

Subproblem 1Set the factor '(2p + 3q)' equal to zero and attempt to solve:

Simplifying
2p + 3q = 0

Solving
2p + 3q = 0

Move all terms containing p to the left, all other terms to the right.

Add '-3q' to each side of the equation.
2p + 3q + -3q = 0 + -3q

Combine like terms: 3q + -3q = 0
2p + 0 = 0 + -3q
2p = 0 + -3q
Remove the zero:
2p = -3q

Divide each side by '2'.
p = -1.5q

Simplifying
p = -1.5q
Subproblem 2Set the factor '(2p + 3q)' equal to zero and attempt to solve:

Simplifying
2p + 3q = 0

Solving
2p + 3q = 0

Move all terms containing p to the left, all other terms to the right.

Add '-3q' to each side of the equation.
2p + 3q + -3q = 0 + -3q

Combine like terms: 3q + -3q = 0
2p + 0 = 0 + -3q
2p = 0 + -3q
Remove the zero:
2p = -3q

Divide each side by '2'.
p = -1.5q

Simplifying
p = -1.5qSolutionp = {-1.5q, -1.5q}