Question

y=x^2+2x-3

x-intercepts

Answer 1

x-intercepts occur where y=0. Set y=0 and solve for x:
\[0=x^2+2x-3\]
The right side will factor:
\[0=(x+3)(x-1)\]
Okay from there?

Answer 2

x-intercepts are where y=0
\[0=(x+3)(x-1)\]
so intercepts are at:
\[x=-3, x=1\]