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Mathematics 19 Online
OpenStudy (anonymous):

solve

OpenStudy (anonymous):

OpenStudy (anonymous):

would these be the same principal they dont seem the same

OpenStudy (anonymous):

well they do involve many of the same things..... In the first one and the last one... the 3 is separate or is it cuberoot???

OpenStudy (anonymous):

is it\[3\sqrt{?} or \sqrt[3]{?}\]

OpenStudy (anonymous):

for the right triangle.... a= 15 and b = 15 c² = a² + b² = 15² + 15² = 225 + 225 = 450 so c = sqroot(450) __ exact value of c = sqroot(2*3*3*5*5) = 3*5*sqroot(2) = 15√2 in decimals, value of c = 21.21320.... so approximate vale to 3 decimal places is 21.213 rounded to nearest thousandth = 21.213

OpenStudy (anonymous):

\[8\sqrt{12} - 7\sqrt{3} = 8\sqrt{2*2*3} - 7\sqrt{3} = 8*2\sqrt{3} - 7\sqrt{3}\] \[16\sqrt{3} - 7\sqrt{3} = (16 - 7)\sqrt{3} = 9\sqrt{3}\]

OpenStudy (anonymous):

it is not separate in the first or last one

OpenStudy (anonymous):

cuberoot(56) ------------ = cuberoot(56/7) = cuberoot(8) = 2 [becoz 2^3 = 8] cuberoot(7)

OpenStudy (anonymous):

\[\sqrt[3]{2x + 9 + 3} = 9\] cubing both sides, we get 2x + 12 = 729 2x = 729 - 12 x = 717/2 x = 358.5

OpenStudy (anonymous):

\[\sqrt[3]{40x ^{3}} = \sqrt[3]{2*2*2*5*x ^{3}} = 2x \sqrt[3]{5}\]

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