Question

solve

Answer 1

for the 1st problem- what's the number in front of th radical sign?

Answer 2

Is the first one:
\[\sqrt[3]{2x+9+3}=9\ ?\]

Answer 3

yes

Answer 4

1st one: x=358.5

Answer 5

Then, \[2x+12=9^3\]
\[x=\frac{717}{2}\]

Answer 6

what's law of exponents?

Answer 7

Think no. 2= 1.

Answer 8

\[\frac{3^{\frac{3}{4}}}{3^{\frac{1}{4}}}=3^{\frac{3}{4}-\frac{1}{4}}=3^\frac{1}{2}\]

Answer 9

\[\sqrt{x+3}=-10\]
\[x+3=(-10)^2\]
\[x=97\]

Answer 10

\[(\sqrt{10}+5\sqrt{2})(\sqrt{10}-5\sqrt{2})\]
\[(\sqrt{10}+5\sqrt{2})(\sqrt{10}-5\sqrt{2})=\sqrt{10\times 10}-5\sqrt{10\times 2}+5\sqrt{10\times 2}-5\times5\sqrt{2\times 2}\]
\[\sqrt{10\times 10}-5\sqrt{10\times 2}+5\sqrt{10\times 2}-5\times5\sqrt{2\times 2}=10-25\times2=-40\]

Answer 11

is this last one an exact answer

Answer 12

Yes

Answer 13

thanks

Answer 14

\[\frac{\sqrt[3]{56}}{\sqrt[3]{7}}=\sqrt[3]{\frac{56}{7}}=\sqrt[3]{8}=2\]